2x^2+2=15490

Solution for 2x^2+2=15490 equation:

2x^2+2=15490

We move all terms to the left:

2x^2+2-(15490)=0

We add all the numbers together, and all the variables

2x^2-15488=0

a = 2; b = 0; c = -15488;
Δ = b2-4ac
Δ = 02-4·2·(-15488)
Δ = 123904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{123904}=352$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-352}{2*2}=\frac{-352}{4}
=-88
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+352}{2*2}=\frac{352}{4}
=88
$